In the given reaction,only one alkene undergo | vedclass

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(B) The reaction involves the ozonolysis of a diene. Ozone $(O_3)$ is an electrophile and preferentially attacks the double bond with higher electron

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(B) The reaction involves the ozonolysis of a diene. Ozone $(O_3)$ is an electrophile and preferentially attacks the double bond with higher electron density. In the given molecule,the double bond conjugated with the $-OMe$ group has higher electron density due to the $+R$ effect of the methoxy group. $1$. Ozonolysis $(O_3, Me_2S)$ of this double bond cleaves the ring to form an aldehyde and a ketone group. $2$. Subsequent treatment with $NaBH_4$ selectively reduces the aldehyde group to a primary alcohol while leaving the ketone (or ester-like carbonyl) unaffected in this specific context,leading to the final product $(P)$ as shown in the solution image.

In the given reaction,only one alkene undergoes preferential oxidation by electrophilic ozone. Identify the product $(P)$ of the given reaction.

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